Smallest 4 digit number divisible by 24 15 36

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WebbThe smallest 4 digit number divisible by 24,15 and 36 is a) 1000 b) 1208 c) 1800 d) 1080 Webb22 feb. 2024 · We know that, the greatest 6 digit number is 999999. Let’s assume that 999999 is divisible by 24, 15 and 36 exactly. Then, the LCM (24, 15 and 36) should also divide 999999 exactly. Finding the prime factors of 24, 15, and 36, we get . 24 = 2 × 2 × 2 × 3 . 15 = 3 × 5 . 36 = 2 × 2 × 3 × 3 . ⇒ L.C.M of 24, 15 and 36 = 360

Find the greatest number of 6 digits exactly divisible by 24, 15 and …

WebbLCM of 15, 24 and 36 is 360. Now take a minimum six digit number i.e. 100000. Divide this number by 360 we get remainder 280. So smallest required number will be 100000+ {360 (LCM)-280 (Remainder)}=100080 Sponsored by Orthojoe™ I have neuropathy in my feet and I wear these shoes all day long. Webb22 apr. 2024 · For this number to be divisible by 24, 15 and 36, Required number must be divisible by the LCM of 24, 15 and 36 i.e., by 360. Now on dividing six digit greatest number by LCM we get 279 as remainder. Therefore the greatest number of 6 digits exactly divisible by 24, 15 and 36 = Six digit greatest number – remainder = 999999 – 279 = … the dogg pound let\u0027s play house

Find the smallest 4 - digit number which is divisible by 18, 24 and 32

Webb12 nov. 2014 · The smallest four digit number that is divisible by 288: 288 x 3 = 864 288 x 4 = 1152 Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers. Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32. Recommend (2) Comment (0) person Parthasaradhi M Member since Mar 31, 2024 … Webb6 juni 2024 · Real numbers, Ch... Find the greatest 4 digit number exactly divisible by 24, 15, 36.and the HCF of two numbers is 16 and their product is 3072. Find their LCM. Webb28 juni 2024 · The smallest six digit number exactly divisible by 15,24 and 36 Solution : LCM of 15, 24 and 36 = 360 Smallest six digit number = 100000 Divide 100000 by 360 We get remainder as 280 Subtract 280 from 100000 and add 360 = 100000 - 280 + 360 = 100080 Let us check if it is divisible by 15, 24 and 36 100080/15 = 6672 100080/24 = … the dogged endurance of ‘law \u0026 order’

[Solved] Find out the smallest no. which on division by 24, 32 and 36

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WebbQuestion From - NCERT Maths Class 6 Chapter 3 EXERCISE 3.7 Question – 9 PLAYING WITH NUMBERS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-Find the smallest ... WebbNow, smallest 4 digit number =1000. 1000=288×3+136. Remainder =136. But we need to find a number where the remainder is 0. Required … the doggarieWebbQuestion : The smallest 4 digit number divisible by 24,15 and 36 is a) 1000 b) 1208 c) 1800 d) 1080 Doubt by Zoha Solution : Coming Soon. Labels: 1 , doubts , MCQ Deleted Syllabus of class X Mathematics (2024-2024) The mean of the following frequency distribution is 25. Find . . . the dogged endurance of ‘law \\u0026 order’

"Webb30 mars 2024 · Let’s first find smallest number divisible by 18, 24, 32 Smallest number divisible by 18, 24, 32 = LCM of 18, 24, 32 LCM of 18, 24, 32 LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288 ∴ 288 is the smallest number divisible by 18, 24, 32 Now, We need to find smallest 4-digit number divisible by 18, 24, 32 Smallest 4 digit number = 1000 we divide 1000 by … " - Smallest 4 digit number divisible by 24 15 36

Smallest 4 digit number divisible by 24 15 36

Webb8 apr. 2024 · This is the smallest four digit number divisible by 18, 24 and 32. Hence 1152 is the smallest four digit number divisible by 18, 24 and 32. Note: Students generally make mistakes in factorization of a number which is the crucial step in this question. Factorization always starts from 2 and moves on to higher primes. WebbSolution. Hey, The answer is : 9720. Here is a step - by - step procedure to find the greatest four digit number that is exactly divisible by 15,24,36. Find the LCM (Least common …

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WebbDivisibility by 3 or 9 [ edit] First, take any number (for this example it will be 492) and add together each digit in the number (4 + 9 + 2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9). WebbSolution: We will be using the concept of LCM (Least Common Multiple) to solve this. We know that the smallest 4-digit number is 1000. Hence,the LCM of 18, 24 and 32 is calculated as shown below, Therefore, LCM of 18, 24 and 32 = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288. Thus, we have 288 as the smallest number, which is exactly divisible by 18 ...

WebbSolution The given numbers are 15, 20, 24, 32, and 36. The smallest number divisible by the numbers given above will be their LCM. LCM = 2 5 × 3 2 × 5 = 1440 ∴ The least number divisible by 15, 20, 24, 32 and 36 is 1440. Concept: Tests for Divisibility of Numbers Is there an error in this question or solution? Webb10 okt. 2024 · Solution : The smallest 4 digit number which is divisible by 18, 24, and 32 will be a multiple of their LCM. Therefore, LCM of 18, 24 and 32 is, 18 = 2 × 3 × 3 24 = 2 × 2 × 2 × 3 32 = 2 × 2 × 2 × 2 × 2 LCM of 18, 24 and 32 = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288 Required smallest 4 digit number which is divisible by 18, 24 and 32 is a multiple of 288.

Webb3 apr. 2016 · On dividing 10000 by 480 we get 400 as a remainder. [∵ 10000 = 480 × 20 + 400] ∴ Smallest 5 digits number divisible by 12, 24, 48, 60 and 96 = 10000 – 400 + 480 = 10080. Download Solution PDF. Share on Whatsapp. Webb21 maj 2024 · lcm=15=3×5. 24=2×2×2×3. 36=2×2×3×3. lcm =2^3×3^2×5. =360. now divide largest 6digit no 999999 by 360. remainder=279. now 999999-279=999,720 so …

Webb26 juni 2016 · 24 - 19 = 5. 32 - 27 = 5. 31 - 31 = 5. The difference between divisors and reminders is the same in all. According to the question, we have. The LCM of (24, 32 and 36) = 288. Now, The smallest number = LCM - 5. ⇒ 288 - 5. ⇒ 283. ∴ The smallest number is 283, divisible by 24, 32 and 36 and leaves the remainder 19, 27 and 31 respectively.

Webb10 okt. 2024 · Given: 24, 15 and 36. To find: Here we have to find the greatest number of 6 digits exactly divisible by 24, 15 and 36. Solution: The greatest 6-digit number $=$ 999999. LCM is the least common multiple of any three numbers and to find the greatest 6-digit number we have to check if 999999 is divisible by the LCM of 24, 15 and 36. the dogg songsWebb27 aug. 2024 · 24 = 23 × 3. 36 = 22 × 32. LCM = product of greatest power of each prime factor involved in the numbers = 23 × 32 × 5 = 360. Now, the greatest four digit number … the dogger houseboat amsterdam the dogged dogmatistWebb10 okt. 2024 · So, LCM of 18, 24 and 36 is 72. But we want the least 4 digit number, which is exactly divisible by 18, 24 and 36. Smallest 4 digit number = 1000. Now, 1000 = (13 $\times$ 72) + 64. Next higher quotient is 14. So, the required number = 14 $\times$ 72 = 1008. Hence, the required number is 1008, which is exactly divisible by 18, 24 and 36. the dogger bank wind farmWebbThe smallest 4 digit number divisible by 24,15 and 36 is a) 1000 b) 1208 c) 1800 d)1080 12. The largest number which exactly divides 280 and 1245 leaving remainders 4 and 3respectively is… a) 36 b) 54 c) 138 d) 72 13. The ratio of LCM and HCF of the least composite and the least prime numbers is a) 1:2 b) 2:1 c) 1:1 d) 1:3 14. the doggerWebb22 apr. 2024 · For this number to be divisible by 24, 15 and 36, Required number must be divisible by the LCM of 24, 15 and 36 i.e., by 360. Now on dividing six digit greatest … the dogger houseboatWebbFour digit numbers (4-digit numbers) are numbers that have four digits in them. They range from 1000 to 9999. Therefore, there are a total of 9000 4-digit numbers. … the doggery auckland